32x^2+6x^2=x^-x

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Solution for 32x^2+6x^2=x^-x equation: 



32x^2+6x^2=x^-x

We move all terms to the left:

32x^2+6x^2-(x^-x)=0

We add all the numbers together, and all the variables

38x^2-(x^-x)=0

We get rid of parentheses

38x^2-x^+x=0

We add all the numbers together, and all the variables

38x^2=0

a = 38; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·38·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{76}=0$

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